Question

If ax+by=a²–b²and bx+ay=0 then the value of x+yis​

Answer 1

Answer:

STEP BY STEP EXPLANATION:-

Given,

ax+by=a^2-b^2 ......(1)

bx+ay=0 .......(2).

Now adding (1) and (2) we get,

x(a+b)+(a+b)y=a^2-b^2

or, (a+b)(x+y)=a^2-b^2

or, (a+b) (x+y) =(a+b) (a-b)

or, x+y=a−b.

ANS. X+Y=A-B

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