If ax = t² + t + 4 m/s² and ay = 8t m/s² then at t = 1 s, the angle θ made by acceleration with x-axis is
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Answer:
53°
Explanation:
let net acceleration be a
ax= acosø= t²+t+4
ay=asinø= 8t m/s
a= sqrt( ax²+ay²)
at t=1
ax= 6m/s²
ay= 8m/s²
a= sqrt(6²+8²)= 10m/s²
angle made with x axis means x component of a
which is acosø
acosø= 6
10cosø=6
cosø= 6/10
cosø= 3/5= 53°
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