if ax³+3x²-13 and 2x³-5x+a are divided by (x-2),the remainder is same.find the value of a.
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equate both the equation and fill the value of x=2 . ANSWER is a=1
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Remainder for a polynomial in x, P(x) on division by (x-2) is given by P(x=2).
P(x) = a x³ + 3 x² - 13
P(2) = a * 8 + 12 - 13 = 8 a -1
Remainder for Q(x) = 2 x³ - 5 x + a
is Q(2) = 6 + a
given 8 a - 1 = 6 + a
solving a = 1
P(x) = a x³ + 3 x² - 13
P(2) = a * 8 + 12 - 13 = 8 a -1
Remainder for Q(x) = 2 x³ - 5 x + a
is Q(2) = 6 + a
given 8 a - 1 = 6 + a
solving a = 1
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