Question

If AxA has 16 elements, S={(a, b) belong to AXA :a<b} ;(-1,2) and (0,1)are two elements of S, then find the remaining elements of S,​

Answer 1

Step-by-step explanation:

For A×A there are total 16 elements 4 are given -1;0;1;2 Now multiply (-1;0;1;2×-1;0;1;2) =(-1;-1);(-1;0);(-1;1);(-1;2);(0;-1);(0;0);(0 1);(0;2);(1;-1);(1;0);(1;1);(1;2);(2;-1);(2;0);(2;1);(2;2)

Answer 2

Answer:

Total number of elements in the set S = (-1,0), (-1,1), (-1,2), (0,1), (0,2), (1,2)

Remaining element of S other than (-1,2) and (0,1) are = (-1,0), (-1,1), (0,2), (1,2)

Step-by-step explanation:

S={(a, b) belong to AXA :a<b}

S is a set in which the elements are denoted as (a,b) where

1. a is less than b and

2. (a,b) belongs to AXA

Note: There are only 6 elements in AXA satisfies the above conditions.