Question

IF AYUSH THROW A BALL AT THE SPEED OF 20 M / S IN THE SKY. THEN WHAT DISTANCE THE BALL COVERED IN 2 SECONDS (HINT : CALCULATE HEIGHT {G=9.8})​​

Answer 1

Answer:

v^2-u^2 =2as

⇒-400 = 2×-9.8s

⇒20.4=s (approximately)

Answer 2

Answer:

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