Question

If b = 0, c < 0, is it true that the roots of x

2 + bx + c = 0 are numerically equal and

opposite in sign? Justify

Answer 1

Answer:

Applying b=0,c<0

x2+bx+c=0

x2+0+c=0

x2= -c

x=± √-c

x=√-c , x= - √-c

Thus roots are numerically equal and opposite in sign. So,the given statement is true