Math, asked by loh234123, 11 hours ago

if b= 3√2,a=3,A=30 degrees, then B=?​

Answers

Answered by jancyjoji19
0

Answer:

First of all, from the basic rules of trigonometry, sin\thetasinθ or cos\thetacosθ have a maximum value of 1.

Therefore, in order for sin3a+cos2bsin3a+cos2b to be equals to 2, this means that both 'sin3a' and 'cos2b' have reached their maximum value of 1.

Hence,

\begin{gathered}sin3a=1\:\:\:and\:\:\:cos2b=1\\3a=90^o\:\:\:\:and\:\:\:\:2b=0^o\\a=30^o\:\:\:\:\:and\:\:\:\:b=0^o\end{gathered}

sin3a=1andcos2b=1

3a=90

o

and2b=0

o

a=30

o

andb=0

o

Now, we need to evaluate:

\begin{gathered}cos2a+sin3b\\=cos2(30^o)+sin3(0^o)\\=cos60^o+sin0^o\\=\frac{1}{2}\end{gathered}

cos2a+sin3b

=cos2(30

o

)+sin3(0

o

)

=cos60

o

+sin0

o

=

2

1

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