if b = 8d - c, and a = d/3, what is the average(arithmetic mean) of a, b,c ,d?
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Answer:
given
b=8d-c
a=d/3
average =sum/total no.of terms
sum=a+b+c+d=a+8d-c+c+d
=a+9d=a+9(3a)
=a+27a
=28a
total no.of terms=4
arithmetic mean=28a/4
answer=7a
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