If b=a+a^2+a^3 +....prove that a=b/(1+b)
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Answer:
If b = a + a^2 + a^3 + ....., a = b / ( 1 + b ).
Step-by-step explanation:
We know,
Sum of ∞ terms of a GS is given by a / ( 1 - r ) where a is the first term and r is the common ratio of the consecutive terms.
Here, a + a^2 + a^3 + ..... forms a GS of infinite terms
First term of the GP is a.
Common ratio of the consecutive terms is a { a^2 / a or a^3 / a^2 }
On the basis of the given formula.
= > b = a / ( 1 - a )
= > b( 1 - a ) = a
= > b - ab = a
= > b = a + ab
= > b = a( 1 + b )
= > b / ( 1 + b ) = a
Henceforth, a = b / ( 1 + b ).
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