Question

$({2}^{ - 1} + {4}^{ - 1} + {6}^{ - 1} + {8}^{ - 1} )^{x} = 1$
please give me answer its urgent

Answer 1

Always, $a^{0}=1$
Hence $X=0$

Answer 2

Answer:

Step-by-step explanation:

(1/2 +1/4 1/6 +1/8 )^x =1

{(12+6+2+3)/24}^x =1

(23/24)^x=1

(23/24)^x= (23/24)^0

x=0 answer