If b is a digit such that 24b3 is divisible by 9, find the value of b.
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Answered by
0
Step-by-step explanation:
B=0
Coz
When we have to divide any sum by 9
Then sum of digits should be equal to multiple of 9.
That's why i put 0 here
2403/9=267
Answered by
0
Answer:
Step-by-step explanation:
As 24b3 is divisible by 9, 2+4+b+3 is divisible by 9.
So, b+9 is divisible by 9.
Therefore, b is either 1 or a multiple of 9
i.e., b=1 (or)9(or)18,etc.
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