If B is the mean proportional of A and C then (a-b)^2: ( b-c)^2?
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Since b is the mean proportional of a and c, b2=ac,i.e.,b=ac.
∴(b−c)3(a−b)3=(ac−c)3(a−ac)3=[c(a−c)]3[a(a−c)]3=(c)3(a−c)3(a)3(a−c)3.
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