Physics, asked by sawianwanda, 11 months ago

two points 2.5x10 ^7 C and -2.5x10^-7C are located at points (0,0,-15cm) and (0,0,-15cm) the magnitude of electric dipole moment of the system is

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Answered by Anonymous
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Correct Question

Two points 2.5x10 ^7 C and -2.5x10^-7C are located at points (0,0,15cm) and (0,0,-15cm) the magnitude of electric dipole moment of the system is

AnswEr :

  • Charges (Q) = 2.5 × 10^-7 C and -2.5 × 10^-7 C

The charges are placed at (0,0,15) and (0,0,-15) respectively. Thus,the length of the dipole is 30 cm

  • Dipole Length (2a) = 30 cm = 30 × 10^-2 m

Dipole Moment is given by :

\sf \vec{P} = 2a | Q |

Putting the values,we get :

\longrightarrow \sf \vec{P} = 30 \times 10^{-2}  \times 2.5 \times 10^{-7} \\ \\ \longrightarrow \sf \vec{P} = (25)(3) \times 10^{-7-2} \\ \\ \huge{\longrightarrow \sf \vec{P} = 75 \times 10^{-9} \ Cm}

Dipole Moment is 75 × 10^-9 Cm

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