If b is the mean proportional of a and c then (a-b)^3 : (b-c)^3?
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Answered by
13
A/q
(a+c)÷2=b
a+c=b+b
a-b=b-c
therefore
(a-b)^3:(b-c)^3
(b-c)^3:(b-c)^3
=1
(a+c)÷2=b
a+c=b+b
a-b=b-c
therefore
(a-b)^3:(b-c)^3
(b-c)^3:(b-c)^3
=1
Answered by
18
the answer is a^3/b^3
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