Question

if b(x)= x^3-16x^2 +11 x -6 then find that x=1,2,3, are the zeros of b (x) or not ​

Answer 1

Answer:

None of them is a zero of b (x)

Step-by-step explanation:

b(1) = 1^3 - 16(1^2) + 11(1) - 6

     = 1 -16 +11 -6

     = -10

b(2) = 2^3 - 16(2^2) + 11(2) - 6

      = 8 - 64 + 22 - 6

      = -40

b(3) = 3^3 -16(3^3) + 11(3) -6

      = 9 - 432 + 33 - 6

      = -396

Hence, none of them is a zero of b (x)