if (b2-b1)(b3-b1)+(a2-a1)(a3-a1)=0 then find the circumcentre of the triangle having its vertices are (a1,b1)(a2,b2)(a3,b3)
Answers
Answered by
6
Answer:
(A2+A3/2),(b2+b3/2)
Step-by-step explanation:
Plzz mark as brainliest
Attachments:
Similar questions