Question

if bc=CD
find angle abc
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Answer 1

As we see here ∠ACB = ∠ACD + ∠BCD.

We could find ∠ACD inside the triangle.

In the triangle ACD, we have ∠A as a supplementary angle of 138°.

→ ∠A + 138° = 180° → ∠A = 42°

In the triangle ACD, we have ∠D=116°.

In the triangle ACD, we have ∠A + ∠C + ∠D = 180°.

→ 42° + ∠C + 116° = 180° → ∠ACD = 22°

We can find the remaining angle in triangle BCD.

In the triangle BCD, the sum of the same angles is 22°.

→ 2∠BCD = 22° → ∠BCD = 11°

And therefore ∠ACB = 22° + 11° = 33°.

Answer 2

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