Question

If bcos θ = a, then prove that cosec θ + cot θ = √(b+a)/(b-a).

Answer 1

cosQ =a/b
then other sides will be √b2-a2
sinQ=√b2-a2/b

Answer 2

tan θ + cot θ = sec θ . cosec θ


L.H.S


tan θ + cot θ


(sin θ /cos θ) + ( cos θ / sinθ)


[ tan θ = (sin θ /cos θ) , cot θ=  ( cos θ / sinθ)]


( sin²θ + cos²θ/ cos θ sin θ)


1/ cos θ sin θ


1/ cos θ × 1/sin θ


Sec  θ . Cosec  θ


[ Sec  θ  = 1/cosθ , Cosec  θ = 1/ sin θ ]


L.H.S = R.H.S


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