Question

if benzoic acid dimerizes to 60% in benzene than van't hoff factor will be

Answer 1

The van't hoff factor for 60% degree of association will be 0.7

Explanation :

The dimerzification of benzoic acid is given by the equation,

2C₆H₅COOH------> (C₆H₅COOH)₂

given the degree of association, α = 60% = 0.6

after association the vant hoff factor is given by the relation,

i = 1 - α/2

= 1 - 0.6/2

= 1 - 0.3

=> i = 0.7

Hence the van't hoff factor for 60% degree of association will be 0.7