Question

If Binomial distribution with n =8 and mean = 2 find P and standard deviation ​

Answer 1

Answer:

The answer is $\sqrt{\dfrac{3}{2}}$

Step-by-step explanation:

For binomial distribution with $n$  trials and having probability of success $p$

          $\boxed{\text{Mean } =np \text{ and variance }=npq, \text{standard deviation } =\sqrt{npq}}$

Here given $n=8$, mean $np=2$

           $\Rightarrow p=\dfrac{2}{n}=\dfrac{2}{8}=\dfrac{1}{4}$

So probability of not success $q=1-p=1-\dfrac{1}{4}=\dfrac{3}{4}$

Therefore standard deviation

                         $=\sqrt{(8)(\dfrac{1}{4})(\dfrac{3}{4})}=\sqrt{\dfrac{3}{2}}$