Question

​If block A has a velocity of 0.6m/s to the right, determine the velocity of block B

Answer 1

See attachment , you forgot to attach it .

This can be solved with help of constraints equation ,
As you can see , a string is attached with block A , and three string is folded with pley which is attached with B.
e.g., $\bold{x_B=3x_A}$
now, differentiate with respect to x
$\bold{v_B=3v_A}$

Given, $\bold{v_A}$ = 0.6 m/s [to the right ]
$\bold{v_B}$ = 0.6 × 3 = 1.8 m/s [ downward ]

Answer 2

Answer:

hey there here is ur ans

Explanation:

as from the figure we can understand that tension in the three strings is acted over the string of B

so we know that f = m.a

                  => (3T * V1) + (-T * V2) = 0

                  => 3T V1 - T V2 = 0

           SO  => 3 V1 = V2

                  => V1 = 0.6 .....(GIVEN)

                  => V2 = 1.8 m/s

thanks

regards Tanvi