If body constrained to move in z direction is subjected to a force given by f=3i^-10j^+5k^. What is the work done by this force in moving the body through a distance of 5m along z axis
Answers
Answered by
8
As the body can move only in z direction then only the component of force in z direction will do work.
W = 5 × 5 = 25 J
Answered by
22
➡GIVEN:-
force = f = 3i-10j+5k
distance=5m along axis=5k
______________________________
▶FORMULA USED:-
work done =(force)(displacement)(cosθ)
=> work done= (force).(displacement)
i.e. work is the dot product or scalar product of force and displacement
______________________________
➡ANSWER:-
=> work = ( 3i-10j+5k)(5k)
=> work= 3(0)(i.i)+(-10)(0)(j.j)+(5)(5)(k.k)
{as we know...
i.i=j.i=k.k=1}
=> work=3(0)+(-10)(0)+5(5)
=> work done= 25joules
_____________________________
hope it helps you
☺☺☺☺
force = f = 3i-10j+5k
distance=5m along axis=5k
______________________________
▶FORMULA USED:-
work done =(force)(displacement)(cosθ)
=> work done= (force).(displacement)
i.e. work is the dot product or scalar product of force and displacement
______________________________
➡ANSWER:-
=> work = ( 3i-10j+5k)(5k)
=> work= 3(0)(i.i)+(-10)(0)(j.j)+(5)(5)(k.k)
{as we know...
i.i=j.i=k.k=1}
=> work=3(0)+(-10)(0)+5(5)
=> work done= 25joules
_____________________________
hope it helps you
☺☺☺☺
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