If body of mass 2kg is projected vertically upward with a velocity 2m/s .Kinetic energy of the body just before striking the ground
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Answer:
m=2kg
v=2m/s or 2ms^-1
Kinetic energy(Ek)=?
By using :
Ek =1/2 mv2 (2 is here square of v)
=1/2 2×22
Or 2/2 2×22
=8 Joule will be its Kinetic energy
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Since the body goes up with speed 2m/s, it will return with the same speed 2m/s
Mass = m = 2kg
Velocity = v = 2m/s
Hence,
KE of the body just before striking the ground = 1/2mv²
KE = 1/2 × 2 × 2²
KE = 1/2 × 2 × 4
KE = 8/2
KE = 4 J
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