Question

If both the magnitude of two charges and distance between them is doubled, then new electrostatic force (if the original force is F) between them will be * (a) F (b) 2F (c) Zero (d) None of these ​

Answer 1

Answer: option is (B) 2f

Answer 2

Given:

original electrostatic force = F

To find:

new electrostatic force F₁ =?

Step-to-step-explanation:

• The electrostatic force is the force produced by charged bodies at rest.
• The electrostatic force will be a force of attraction or force of repulsion.
• This electrostatic force is mathematically expressed as:

$\displaystyle F = k \ \frac{q_1\ q_2}{r^2}$

where

F = electrostatic force

k = Coulomb's constant

q1 = magnitude of one of the charge

q2 = magnitude of another charge

r = distance between two charges

• Consider the original force is F.
• We have to find the new electrostatic force if both the magnitude of two charges and the distance between the charges is doubled.

        q1 = 2 q1

        q2 = 2 q2

         r = 2r

• The new electrostatic force is F₁.

• Put these values in the mathematical expression of electrostatic force.

        $\displaystyle F_1 = k \ \frac{2q_1\ 2q_2}{(2r)^2}$

        $F_1 = \displaystyle k \ \frac{q_1\ q_2}{r^2}$

        F₁ = F

• The new electrostatic force is the same as the original force which is F.

Correct option is :  (a) F