Question

If both the zeroes of the quadratic polynomial ax^2+by+c are equal and opposite in sign,then find the value of b.Explain your answer

Answer 1

Answer:

$\huge\underline\mathfrak{Answer !!}$

The "value of b" is zero.

To find:

The value of b

Solution:

Let us consider f to be one of the zeroes of the quadratic polynomial

Thus, the other zero of the polynomial, which is equal and opposite in sign will be = -f.

We know,

For a quadratic polynomial represented as ,  

Sum of the zeroes =

Thus, the "value of b" for the quadratic polynomial is 0.

Answer 2

/* please verify the polynomial , second term may bx not by */

$Let \: \alpha \:and \: -\alpha \: are \: two \\zeroes \: of \: the \: quadratic \: polynomial \\ax^{2} + bx + c$

$Sum \: of \: the \: zeroes \\= \frac{ - (x - coefficient) }{ x^{2} - coefficient }$

$\implies \alpha + ( -\alpha) = \frac{-b}{a}$

$\implies 0 = \frac{-b}{a}$

$\implies 0 = b$

Therefore.,

$\red { Value \: of \: b } \green { = 0 }$

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