If both x+1 and x-1 are factors of ax^3 +x^2-2x+b,find the values of a and b
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Answered by
5
★ CUBIC RESOLUTION ★
Given function :
ax^3 + x² - 2x + b = 0
For given that x - 1 and x + 1 are factors respectively ,
HENCE , x = 1 and -1 will satisfy the cubic equation
x = 1
a + 1 - 2 + b = 0
x = -1
-a + 1 + 2 + b = 0
Two respective linear equivalents are obtained
a + b = 1
-a + b = -3
Solving them will yield
a = 2 and b = -1
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Given function :
ax^3 + x² - 2x + b = 0
For given that x - 1 and x + 1 are factors respectively ,
HENCE , x = 1 and -1 will satisfy the cubic equation
x = 1
a + 1 - 2 + b = 0
x = -1
-a + 1 + 2 + b = 0
Two respective linear equivalents are obtained
a + b = 1
-a + b = -3
Solving them will yield
a = 2 and b = -1
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Answered by
7
Given cubic polynomial is = ax³+x²-2x+b
also x+1 and x-1 are factors of this polynomial , thus
x= -1,1 must satisfy this equation
Now put x = -1 in the given polynomial we get
a(-1)³+(-1)²-2(-1)+b = 0
=> -a+b+2 +1 = 0
=> b-a = 3 ------------------1
Now put x = 1 , we get
a(1)³+(1)²-2(1)+b=0
=> a+b=1 ----------------2
solving these two
a = 2 and b = -1
also x+1 and x-1 are factors of this polynomial , thus
x= -1,1 must satisfy this equation
Now put x = -1 in the given polynomial we get
a(-1)³+(-1)²-2(-1)+b = 0
=> -a+b+2 +1 = 0
=> b-a = 3 ------------------1
Now put x = 1 , we get
a(1)³+(1)²-2(1)+b=0
=> a+b=1 ----------------2
solving these two
a = 2 and b = -1
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