Ifx=2/3 and are roots of quadratic equation axsquare+7x+b=0 the find value of a and b
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★ QUADRATIC RESOLUTION ★
Here's a general mistake in the given equation , else everything is appropriate according to the configuration :
The given quadratic equation :
ax² - 12x + b = 0
Since , x = 2/3 are the roots , means D = 0 and roots are equal respectively ,
Hence , x -2/3 ( x - 2/3 ) = [ x - 2/3 ]² = 0
Or , furthermore resolved to :
9x² -12x + 4 = 0
Hence , Comparing the coefficients :
ax² -12x + b = 9x² -12x + 4 = 0
Therefore , a = 9 and b = 4
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Here's a general mistake in the given equation , else everything is appropriate according to the configuration :
The given quadratic equation :
ax² - 12x + b = 0
Since , x = 2/3 are the roots , means D = 0 and roots are equal respectively ,
Hence , x -2/3 ( x - 2/3 ) = [ x - 2/3 ]² = 0
Or , furthermore resolved to :
9x² -12x + 4 = 0
Hence , Comparing the coefficients :
ax² -12x + b = 9x² -12x + 4 = 0
Therefore , a = 9 and b = 4
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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