Question

If both x-2 and x-1/2 are factors of px^2+5x+r, show that p=r

Answer 1

Answer:

Px^2+5x+r =(x-2)(x-1/2)or in the rhs solving we get x^2-x/2-2x+1

Px^2+5x+r=x^2-x/2-2x+1

2px^2+6x+2r=2x^2-x+2

On comparasing both sides we

get

P+6+r=1-2

P=r