If both x-2 and x- 1/2 are the factors of px² + 5x + r , Show that p=r
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hence p and r both equal to( -2) therefore p=r
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hey ...!!
here is ur answer.....!!
_________________________________________________________
Let,
p(x)=px²+5x+r.
Since,
x-2 ad x-1/2 are factors of p(x).
p(2)=0 and p(1/2)=0
p×2²+5×2+r=0 and p(1/2)²+5×1/2+r=0
4p+10+r=0 and p/4+5/2+r=0
4p+r=-10 and p+4r+10=0
4
4p+r=-10 and p+4r+10=0
4p+r=-10 and p+4r=-10
4p+r=p+4r
3p=3r
⇒ p=r
_-_-_-_-_-_-&-_-_--_-__--_-_---_-_&-_--_--_-_-_-_-------_-_-_-_-_
thanks....!
here is ur answer.....!!
_________________________________________________________
Let,
p(x)=px²+5x+r.
Since,
x-2 ad x-1/2 are factors of p(x).
p(2)=0 and p(1/2)=0
p×2²+5×2+r=0 and p(1/2)²+5×1/2+r=0
4p+10+r=0 and p/4+5/2+r=0
4p+r=-10 and p+4r+10=0
4
4p+r=-10 and p+4r+10=0
4p+r=-10 and p+4r=-10
4p+r=p+4r
3p=3r
⇒ p=r
_-_-_-_-_-_-&-_-_--_-__--_-_---_-_&-_--_--_-_-_-_-------_-_-_-_-_
thanks....!
raahul072:
thnx....!☺
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