Question

If c>0 and the equation 3ax+ 4bx +C =0 has no real root, then​

Answer 1

Step-by-step explanation:

Let, f(x)=3ax

2

+4bx+c

Now, f(0)=c⟹f(0)>0

∵ the given quadratic equation has no real roots and f(0)>0

∴f(x) will be positive for every real value of x

So, f(−1)>0

⟹3a−4b+c>0

⟹3a+c>4b

Hence, 3a+c>4b