Question

If C is an acute angle in a right triangle ABC, right angled at B, then the value of sinC + cosC is equal to?

Answer 1

then,

sin A = p/h = BC/AC

cos A = b/h = AB/AC

sinA + coaA = AB+BC/ AC

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Answer 2

Answer:

The answer is SinA +CosA=AB+BC/AC

HOPE IT HELPS YOU