Math, asked by saharounak093, 9 months ago

If C is right angle of a ∆ABC, then
(sin²A/sin²B)-(cos²A/cos²B) is equal to
(1)(a²-b²)/ab
(2)(a⁴-b⁴)/a²b²
(3)(a⁴+b⁴)/a²b²
(4)(a²+b²)/ab

Answers

Answered by rishi1121
0

Step-by-step explanation:

(a² + b²)[(a²)² - a²b² + (b²)²] … … [using algebraic formula: a³ + b³ = (a+b)(a²- ab+b²)]. = (a² + b²)[a⁴ - a²b² + b⁴].

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