. If ⁿC₃ = ⁿC₅ , then find the value of n .
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5
Answer:
nCr=(r!)(n−r)!n!
Given, nC3=nC5
=>(3!)(n−3)!n!=5!(n−5)!n!
=>3!×(n−3)×(n−4)×(n−5)!=5×4×3!×(n−5)!
=>(n−3)×(n−4)=5×4
From this, n−3=5
=>n=8
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Answer:
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