Question

if centroid of triangle formed by (p,q), (q,1), (1,p) is the origin , then p^3+q^-3pq​

Answer 1

Step-by-step explanation:

So, (

$( \frac{2p + 1}{3} . \frac{2q + 1}{3} ) = (0.0) \\ or \: \: \: 2p + 1 = 0 \\ or \: \: p = \frac{ - 1}{2} \\ and \: \: \: \: q = - \frac{1}{2} \\ \\ hence. \: {p}^{3} + {q}^{3} - 3pq \\ \: \: = - \frac{1}{8} - \frac{1}{8} - \frac{3}{4 } = - 1$

I hope it will help you to understand the solution ☺️

Please mark it as the brainliest answer ☃️