Question

If chord PQ of a circle have length equal to the radius then the
distance of chord from centre in terms of radius is​

Answer 1

Step-by-step explanation:

Given-

PQ is a chord of a circle with centre O such that OP = OQ = r = PQ when r is the radius of the circle.

To find out h = ON , the distance of PQ from O

Solution-

∆OPQ is equilateral since all its sides = r

Now height of an equilateral triangle with side= a

is √3/2a and it bisects the base at right angle.

Here a= r

= The height = ON = h = √3/2r

But ON is the distance of the chord PQ from O since the perpendicular distance of a chord from the centre bisects the chord at right angle.

So, h = ON = √3/2r is the distance of the chord PQ from O.

Ans- √3/2r

Answer 2

Answer:

$\sqrt[3]{?}$