Question

Two identical resistors each of resistance 15ohm are connected
in
i. series
ii.parallel
in turn to a battery of 6V. Calculate the ratio of power consumed in the combination of resistors in each case

Answer 1

first case

1/Rp = 1/R1 + 1/R2

( by parallel law )

1/Rp = 1/ 15 + 1/15

1/Rp = 2 /15

Rp = 15/2 ohms -------- eq1

now voltage= 6v

current (I) = V/R

I =

6/7.5 ampere

now in series

Rs = R1 +R2

Rs = 30ohms

I = 30/7.5

the ratio are

1:4

Answer 2

Answer:

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