If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of
these circles lies on the third side.?? anyone ??????
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If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lies on the third side. ... Hence, the circle described on AC as diameter must pass through D. Thus, the two circles intersect in D. Now, ∠ADB + ∠ADC = 180°.
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