Question

if circles are drawn with each sides of a triangle of sides 5 cm, 12 cm,13 cm as diameter then with respect to each circle,where would be the third vertex?​

Answer 1

Answer:

AB⊥BC

BD⊥AC

Area(ABC)=

2

1

​

×AB×BC (1)

Area(ABC)=

2

1

​

×BD×AC (2)

Equating (1) and (2)

2

1

​

×AB×BC=

2

1

​

×BD×AC

Let AB=12cm,BC=5cm,AC=13cm

AB×BC=BD×AC

12×5=BD×13

BD=

13

60

​

BD=4.6cm

The lengh of the perpendicular from the opposite vertex to the side whose length is 13 cm=4.6cm

Step-by-step explanation: