Question

if circumference of a circle is 44 cm and the sum of 2 sides of the square is 22 cm, then A) area of circle = area of square B) area of the circle > area of the square C) area of the circle < area of the square D) area of the ciecle = 2 area of the square

Answer 1

hi.
c=44cm
therefore,
$c =\pi \times d$
$\pi = \frac{22}{7}$
$44 =d \times \frac{22}{7}$
$\frac{44}{d} = \frac{22}{7}$
$44 \times 7 = 22 \times d$
$308 = 22d$
$\frac{308}{22} = d$
$d = 14$
diameter=14
raidus=14/2
=7cm
$area \: of \: circle = \pi \times {r}^{2}$
$= \frac{22}{7} \times 7 \times 7$
$= 22 \times 7$
=154cm²

we know that square has equal length sides..,
therefore..,
$x + x = 22$
$x = 11cm$
$area \: of \: square = {side}^{2}$
$= {11}^{2}$
$= 121 {cm}^{2}$

so,
option B) area of circle > area of square is right.