Question

If coefficient of performance of a refrigerator
working between a source and sink is 1.5, then the
efficiency of heat engine working between the same
source and the sink will be
(1) 40%
(2) 25%
(4) 37%
(3) 60%​

Answer 1

Answer:

40%

Explanation:

since, relation b/w coefficient of performance of refrigerator and efficiency of heat engine is

B=(1/n)-1.

Answer 2

The efficiency of heat engine working between the same  source and the sink will be 40 percent.

Explanation:

The relation between coefficient of performance of a refrigerator and the efficiency of heat engine is given by :

$\beta =\dfrac{1-\eta}{\eta}$

Here,

$\beta$ is efficiency of heat engine

$\eta$ is coefficient of performance of a refrigerator

$\eta=\dfrac{1}{\beta +1}\\\\\eta=\dfrac{1}{1.5+1}\\\\\eta=0.4\times 100\\\\\eta=40\%$

So, the efficiency of heat engine working between the same  source and the sink will be 40 percent.

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Efficiency of heat engine

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