Question

the area of a rectangle is 21cm square. if one side exceeds the other by 4 cm, find the dimensions of the rectangle

Answer 1

Length = 7cm
Breadth = 3cm

Answer 2

The dimensions of the rectangle  are 3 cm and 7 cm

Step-by-step explanation:

Let the length of rectangle be x

We are given that one side exceeds the other by 4 cm,

Breadth = x+4

Area of rectangle = Length \times Breadth = $x \times (x+4)=x^2+4x$

We are given that the area of a rectangle is 21cm square

So,$x^2+4x=21$

$x^2+4x-21=0$

$x^2+7x-3x-21=0$

$x(x+7)-3(x+7)=0$

(x-3)(x+7)=0

So, x=3,-7

So, length cannot be negative

So, Length = 3 cm

Breadth = x+4 =3+4=7 cm

Hence the dimensions of the rectangle  are 3 cm and 7 cm

#Learn more:

One side of a rectangle exceeds it's other side by 2 cm if it's area is 195 cm square determine the sides of the rectangle

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