if common ratio and 6th term of a GS are 4 snd 5120 find the first term of the sequence.
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The given G.P. has first term a=5 and the common ratio r=2. Let the nth term be 5120. Then,
a
n
=5120
ar
n−1
=5120
5(2
n−1
)=5120
2
n−1
=1024
2
n−1
=2
10
n−1=10
n=11
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