Question

if compound interest is 1549 rupees for 3year at a rate of 9percent per annum find the value of simple interest?​

Answer 1

Answer:

$\star \: { \red{\bf{c.i = p(1 + \frac{r}{100} )^{n} - 1}}} \\ \\ \sf{1549 = p(1 + \frac{9}{100} )^{3} - 1} \\ \\ \sf{ 1549 = p( \frac{109}{100} \times \frac{109}{100} \times \frac{109}{100}) - 1} \\ \\ \sf{ 1549 = p \times ( \frac{1,295,029}{1000000} - 1)} \\ \\ \sf {1549 = p \times \frac{1,295,029 - 1000000}{1000000} } \\ \\ \sf{1549 = p \times \frac{295,029}{1000000} } \\ \\ \sf{p = \frac{1549 \times 1000000}{295029} } \\ \\ \sf {p = 190.46417 \times 1000000 }\\ \\ { \pink{\bf{p = 190,464,170}}} \\ \\ \\ \star \: { \red{\bf{s.i = \frac{p \times r \times t}{100} }}} \\ \\ \sf{ = \frac{190464170 \times 9 \times 3}{10 0} } \\ \\ \sf{=\frac{ 5.14253259e9}{100} }\\ \\{ \boxed{ \green{ \bf{ s.i = 51,425,325.9}}}}$

hope it helps u❤

Answer 2

Answer:

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