If cos 0 - 4 sin 0 = 1, then
sin 0 + 4 cos e
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0
Answer:
±4
Step-by-step explanation:
Given, cosθ−4sinθ=1
Let sinθ+4cosθ=x
Then (cosθ−4sinθ)
2
+(sinθ+4cosθ)=1+x
2
⇒cos
2
θ+16sin
2
θ+sin
2
θ+16cos
2
θ =1+x
2
⇒x
2
=16
⇒x=±4
Therefore, sinθ+4cosθ=±4
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