Math, asked by abbbcb007, 9 months ago

If cos 0 + sec 0 = 2 then cos²⁰¹⁹0 + sec²⁰¹⁹0 = 2.​

Answers

Answered by pawanbhavanam2
1

Answer:

Step-by-step explanation:

Given cosx+secx=2

we know secx=1/cosx

cos^2x+1/cosx=2

cos^2x-2cosx+1=0

{cosx-1)^2=0

cosx=1 so secx=1

cos^2019x+sec^2019x=1^2019+1^2019

=1+1=2

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