If cos 0 + sec 0 = 2 then cos²⁰¹⁹0 + sec²⁰¹⁹0 = 2.
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Step-by-step explanation:
Given cosx+secx=2
we know secx=1/cosx
cos^2x+1/cosx=2
cos^2x-2cosx+1=0
{cosx-1)^2=0
cosx=1 so secx=1
cos^2019x+sec^2019x=1^2019+1^2019
=1+1=2
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