Question

If cos⁡θ=(2√mn)/(m+n),find the value of sin⁡θ Answer is (m-n)/m+n

Answer 1

Cos θ = Base / hypotenuse = ( 2√mn)/(m+n)

Applying PYTHAGORA'S THEOREM,

Hypotenuse^2 = Perpendicular ^2 + Base ^2

( m + n ) ^2 = P^2 + ( 2√mn) ^2

m ^2 + n ^2 + 2mn = P^2 + 4 mn.

m ^2 + n ^2 + 2mn - 4 mn = P^2

P^2 = m^2 + n^2 - 2 mn

P^2 = ( m - n ) ^2

P = ( m - n )

Sin ⁡θ = Perpendicular / Hypotenuse

Sin θ => ( m - n ) / ( m + n )

Answer 2

Answer:

hope it helped u mate....