If cos^2a-sin^2a=tan^2b prove that tan^2a=cos^2b-sin^2b
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We know that
cos2A+sin2A=1 ,
and it is given that
cos2A−sin2A=tan2B .
From the above two equations:
sin2Acos2A=12(1−tan2B)=12(1+tan2B)=12sec2B
Now:
sin2Acos2A=tan2A1−tan2Bsec2B=tan2Acos2B−sin2B=tan2A.
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