Math, asked by ushukla6665, 11 months ago

If cos^2a-sin^2a=tan^2b prove that tan^2a=cos^2b-sin^2b

Answers

Answered by Anonymous
1

We know that

cos2A+sin2A=1 ,

and it is given that

cos2A−sin2A=tan2B .

From the above two equations:

sin2Acos2A=12(1−tan2B)=12(1+tan2B)=12sec2B

Now:

sin2Acos2A=tan2A1−tan2Bsec2B=tan2Acos2B−sin2B=tan2A.

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