Question

If x2 + 6x = - 9, how many values of x are possible?

Answer 1

The number of possible value of x is "only one (1)".

Step-by-step explanation:

The given equation:

$x^2$ + 6x = - 9

or, $x^2$ + 6x + 9 = 0

To find, the number of possible values of x = ?

∴ $x^2$ + 6x + 9 = 0

⇒ $x^2$ + 2(x)(3) + $3^2$ = 0

Using the algebraic identity,

$(a+b)^2=a^{2} +2ab+b^2$

$(x+3)^2=0$

⇒ x + 3 = 0

⇒ x = - 3

∴ The number of possible value of x = 1

Thus, the number of possible value of x is "only one (1)".