If cos 3Q = sin 2Q,wher 3Q and 2Q are acute angles,find the value of Q.
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cos 3Q= sin 2Q
sin(90°-3Q)= sin 2Q { ∵cos∅ =sin (90° - ∅)}
90-3Q=2Q
90=5Q
5Q=90°
Q=18°
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