Question

if cos(45+x)°= sin 35°, find the value of x​

Answer 1

Hope itt hllpss uhh....

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Answer 2

$\huge\boxed{\huge\boxed{\bold{ANSWER: \ \boxed{\bold{x=10}}\ \ OR\ \ \boxed{\bold{x=-100}}}}}$

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According to $\sin \theta = \cos (90-\theta)=\cos(\theta-90)$

Let θ = 35°

$\sin \theta = \cos (90-\theta)=\cos(\theta-90) \\ \\ \sin35\textdegree=cos(90-35)\textdegree=\cos(35-90)\textdegree \\ \\ \sin35\textdegree=\cos55\textdegree=\cos(-55)\textdegree \\ \\ \sin35\textdegree=\cos(45+x)\textdegree \\ \\ \\ 45+x=55 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 45+x=-55 \\ \\ x=55-45 \ \ \ \ \ \ \ \ \ \ \ \boxed{ OR } \ \ \ \ \ \ \ \ \ \ \ \ x=-55-45\\ \\ x=\bold{10} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\bold{-100}$

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$\boxed{\bold{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ THANK\ YOU.\ :-)) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }}$